**Problem**: A bakery opened yesterday with its daily supply of 40 dozen rolls. Half of viagra at the gas station the rolls were kamagra uk paypal sold by noon, and 80 percent of the remaining rolls were sold between noon and closing time. How many dozen rolls had not been sold when the bakery closed yesterday?

**Solution**: If half of the rolls were sold kamagra oral jelly by noon, ⅟₂*40 dozen = 20 dozen rolls were sold by gold viagra noon and 20 dozen rolls remained. 80%, or 0.8 of the remaing rolls = .8*20 dozen = 16 dozen were sold by closing. Thus, there were 20 dozen – 16 dozen = 4 dozen rolls remaining at closing.

**Strategy**: Percents can be written as fractions or decimals. When working with percents, http://cialisonline-bestoffer.com/ the word “OF” means to multiple. In this problem, half of 40 dozen translates to ⅟₂*40 dozen = 20 dozen. Also, 80% of 20 dozen translates oralni gel kamagra to .8*20 dozen = pharmacy graduates in canada 16 dozen.

**Problem**:

A carpenter constructed a rectangular sandbox with a capacity of 10 cubic feet. If the carpenter were to make a similar sandbox twice as long, twice as wide, and twice as high as the first sandbox, what would be the capacity, in cubic feet, of the second sandbox?

**Solution**:

The capacity (volume) of a rectangular box is calculated as length * width * height (l*w*h).

So, the equation is l*w*h = 10.

Because the new sandbox is twice as long, twice as wide, and twice as high, its capacity is:

(2*l)*(2*w)*(2*h) = 8*l*w*h.

Substituting 10 for the value of l*w*h gives

8*l*w*h = 8*10 = 80.

**Strategy**:

Capacity and volume are interchangeable. The equation for the volume of a rectangular box is:

Volume = Length*Width*Height or V=L*W*H

**Problem**:

0.1 + (0.1)^{2} + (0.1)^{3} =

**Solution**:

0.1 + (0.1)^{2} + (0.1)^{3} = 0.1 + 0.01 + 0.001 = 0.111

**Strategy**:

Be sure to line up your decimals before you add (not necessary for multiplication).

**Problem**:

On Monday, a person mailed 8 packages weighing an average (arithmetic mean) of 12 3/8 pounds, and on Tuesday, 4 packages weighing an average of 15 1/4 pounds. What was the average weight, in pounds, of all the packages the person mailed on both days?

**Solution**:

The average weight of the packages is the total weight divided by the number of packages:

Avg. = Total/#of items, or

Total = Avg. * # of items

Using this form of the average equation, the total weight for all 12 packages is:

8*12⅜ + 4*15⅟_{4} = 99 + 61 = 160.

The number of packages is 8 + 4 = 12.

Thus, the average weight is 160 / 12 = 13⅓.

**Strategy**:

With twice as many packages with average 12⅜ as 15⅟_{4}, the answer will be ⅓ of the distance from 12⅜ to 15⅟_{4} (think of it as two packages weighing 12⅜ and one weighing 15⅟_{4}). Also, one can immediately eliminate the choices weighing more than 15⅟_{4} as the averages must be less than that.

**Problem**:

When Leo imported a certain item, he paid a 7% import tax on the portion of the total value of the item in excess of $1,000. If the amount of the import tax that Leo paid was $87.50, what was the total value of the item?

**Solution**:

Writing the problem as an equation gives 7% * (C-$1000) = $87.50 where C is the cost in dollars.

C – $1,000 = $87.50 / 7% => Divide both sides of the equation by 7%

C – $1,000 = $87.50 / 0.07 = $1,250 => Change 7% to a decimal, then divide

C = $1,250 + $1,000 = $2,250 => Add $1,000 to both sides to get the answer

**Strategy**:

The phrase “in excess of” refers signals subtraction. Subtract the total amount from the amount that is required to get the excess. This is typical for some percent problems involving sales tax or sales commission.

**Problem**: Raffle tickets numbered consecutively from 101 through 350 are placed

in a box. What is probability that a ticket selected at random will have a number with a hundreds digit of 2?

**Solution**: There are 350 – 101 + 1 = 250 raffle tickets sold, 299 – 200 kamagra oral jelly + 1 = 100 of which have hundreds digit 2. So the probability is 100 / 250 = 2/5 = 40%

**Strategy**: To find the number of numbers in a range of numbers, including the 25 mg dose of viagra endpoints, subtract the largest number from the smallest number, then add 1. On the other hand, to find the number of numbers in

a range of numbers, excluding the endpoints, subject the largest number from the smallest number, then subtract 1.

**Problem**:

Which of the following is the value of √(^{3}√(0.000064))?

**Solution**:

One way to go about this calculation – and possibly the simpliest way – is to simplify the exponents before performing any calculations. Rewrite this problem as:

(((64*10^{-6})^{1/3})^{1/2}) (multiply the exponents together – see rule below)

= (64*10^{-6})^{1/6} (distribute the exponent ^{1/6 }across the 64 and the 10)

= 64^{1/6} * 10^{-1} (simplify exponents)

= 2 / 10 = .2

**Strategy**:

Knowing your exponent rules is critical. Remember that a square root can be written as the (1/2) exponent. Similarly, a cubic root can be written as the (1/3) exponent (and so on…).

Remember these rules (where a and b represent any base, and m and n represent any exponent):

(a^{m})^{n} = a^{mn}

(ab)^{n} = a^{n} b^{n}

1 = a^{-n}

a^{n}

**Problem**:

When 1/10 percent of 5,000 is subtracted from 1/10 of 5,000, the difference is

**Solution**:

1/10% of 5,000 = 0.001 * 5,000 = 5

1/10 of 5,000 = 500

So, the difference between 500 and 5 is 495.

**Strategy**:

A few tips for problems like this one:

– We know the numbers are different so you can eliminate 0 as an answer.

– The values are going to be 5, 50, 500, or 5,000; some version of 5 with some 0s following it. Therefore, when you subtract one of these numbers from another, you’ll end up with a number that starts with 4 so you can eliminate B & E as answers.

– It might be simplier to think of 1/10% as 1/10th of 1% rather than writing 1/10% as a decimal then multiplying. 1% of 5,000 is 50 (moving decimal over 2 spaces) and 1/10th of 50 is 5.

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